JEE Main Physics Simple Harmonic Motion Previous Year Questions with Solutions is given below.
Multiple Choice with ONE correct answer
1.Two bodies M and N of equal masses are suspended from two separate massless springs of spring constants k1 and k2 respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of vibration of M to that of N is [1988-1mark]
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3.The period of oscillation of a simple pendulum of length L suspended from the roof of a vehicle which moves without friction down an inclined plane of inclination a is given by [2000-2 marks]
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4.A particle executes simple harmonic motion between x = -A and x = +A. The time taken for it to go from 0 to A/2 is Tt and to go from A/2 to A is T2. Then [2001-2 marks]
a) T1 < T2 b) T1 > T2 c)T1 = T2 d) T1 = 2T2
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Option (a) represents the correct answer. Infact, velocity of particle goes on decreasing from maximum value to zero as, the particle travels from mean position to extreme position.
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6.A simple pendulum is oscillating without damping. When the displacement of the bob is less than maximum, its acceleration vector is a correctly shown in [2002]
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7.(i) For a particle executing SHM the displacement x is given by x=A cos ut, Identify the graph which represents the variation of potential energy (PE) as a function of time t and displacement x
a)5/6 b)6/5 c)1 d)4/5
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