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JEE Main 2023 exam postponed in April

  JEE Main 2023 Exam in April:   The Joint Entrance Examination (JEE) Main 2023 exam date will soon be announced by the NTA.  Engineering aspirants have requested the National Testing Agency (NTA) to hold the first session of the Joint Entrance Examination (JEE) Main 2023 in April to prevent a potential conflict with the Class 12 board exams  With the hashtag #jeemainsinapril, some of them have announced that they will be taking the CBSE board’s practical and theoretical exams in January and February. When it becomes available, candidates can check the JEE Main 2023 detailed notification by going to the jeemain.nta.nic.in 2023 IIT JEE official website Engineering hopefuls have gone to Twitter to urge a decision on the Joint Entrance Test (JEE) Mains examination from the administrative agency, NTA, as there has been no official announcement on when the JEE Main 2023 will be held. We humbly ask for your consideration as students, as we already had our board practical i...
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Gravitational Notes for jee and neet

  Gravitation  Notes for jee main and advance  The Universal Law of Gravitation and Gravitational Constant In the universe, everybody attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. This attraction force is known as the gravitational force. where M 1  and M 2  are the masses of two bodies, R is the distance between and G is the Gravitational Constant. G = 6.67 × 10 -11  Nm 2 (kg) -2 1. Gravitational force is always attractive in nature. 2. Gravitational force is independent of the nature of the intervening medium. 3. Gravitational force is conservative in nature.  4. It is a central force so it acts along the line joining the center of the two interacting bodies and it obeys inverse square law.   Acceleration due to Gravity of the Earth and its Variation   The gravitational pull exerted by the earth is called gravit...
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Jee main and neet question of kinematics

Q1: A piece of wood of mass 0.03 kg is dropped from the top of a 100 m height building. At the same time, a bullet of mass 0.02 Kg is fired vertically upward, with a velocity 100 m/s, from the ground. The bullet gets embedded in the wood. Then the maximum height to which the combined system reaches above the top of the building before falling below is (g = 10 m/s) 10 m 30 m 20 m 40 m Solution Suppose both collide at the point P after time t. Time taken for the particles to collide, t = d/v rel  = 100/100 = 1s Speed of wood just before collision =gt = 10m/s Speed of bullet just before collision v -gt = 100 -10 = 90 m/s Before 0.03 kg ↓ 10 m/s 0.02 kg ↑ 90 m/s   After ↑ v 0.05 kg Now, the conservation of linear momentum just before and after the collision -(0.03)(10) + (0.02)(90) = (0.05)v ⇒ v = 30 m/s The maximum height reached by the body a = v 2 /2g = (30) 2 /2(10) = 45 m (100 -h) = ½ gt 2  = ½ x 10 x1 ⇒h = 95 m Height above tower = 40 m Answer: (d) 40 m Q2: A passenger ...
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